python实现扫雷小游戏的方法-创新互联
这篇文章主要讲解了python实现扫雷小游戏的方法,内容清晰明了,对此有兴趣的小伙伴可以学习一下,相信大家阅读完之后会有帮助。
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import random from enum import Enum BLOCK_WIDTH = 30 BLOCK_HEIGHT = 16 SIZE = 20 # 块大小 MINE_COUNT = 99 # 地雷数 class BlockStatus(Enum): normal = 1 # 未点击 opened = 2 # 已点击 mine = 3 # 地雷 flag = 4 # 标记为地雷 ask = 5 # 标记为问号 bomb = 6 # 踩中地雷 hint = 7 # 被双击的周围 double = 8 # 正被鼠标左右键双击 class Mine: def __init__(self, x, y, value=0): self._x = x self._y = y self._value = 0 self._around_mine_count = -1 self._status = BlockStatus.normal self.set_value(value) def __repr__(self): return str(self._value) # return f'({self._x},{self._y})={self._value}, status={self.status}' def get_x(self): return self._x def set_x(self, x): self._x = x x = property(fget=get_x, fset=set_x) def get_y(self): return self._y def set_y(self, y): self._y = y y = property(fget=get_y, fset=set_y) def get_value(self): return self._value def set_value(self, value): if value: self._value = 1 else: self._value = 0 value = property(fget=get_value, fset=set_value, doc='0:非地雷 1:雷') def get_around_mine_count(self): return self._around_mine_count def set_around_mine_count(self, around_mine_count): self._around_mine_count = around_mine_count around_mine_count = property(fget=get_around_mine_count, fset=set_around_mine_count, doc='四周地雷数量') def get_status(self): return self._status def set_status(self, value): self._status = value status = property(fget=get_status, fset=set_status, doc='BlockStatus') class MineBlock: def __init__(self): self._block = [[Mine(i, j) for i in range(BLOCK_WIDTH)] for j in range(BLOCK_HEIGHT)] # 埋雷 for i in random.sample(range(BLOCK_WIDTH * BLOCK_HEIGHT), MINE_COUNT): self._block[i // BLOCK_WIDTH][i % BLOCK_WIDTH].value = 1 def get_block(self): return self._block block = property(fget=get_block) def getmine(self, x, y): return self._block[y][x] def open_mine(self, x, y): # 踩到雷了 if self._block[y][x].value: self._block[y][x].status = BlockStatus.bomb return False # 先把状态改为 opened self._block[y][x].status = BlockStatus.opened around = _get_around(x, y) _sum = 0 for i, j in around: if self._block[j][i].value: _sum += 1 self._block[y][x].around_mine_count = _sum # 如果周围没有雷,那么将周围8个未中未点开的递归算一遍 # 这就能实现一点出现一大片打开的效果了 if _sum == 0: for i, j in around: if self._block[j][i].around_mine_count == -1: self.open_mine(i, j) return True def double_mouse_button_down(self, x, y): if self._block[y][x].around_mine_count == 0: return True self._block[y][x].status = BlockStatus.double around = _get_around(x, y) sumflag = 0 # 周围被标记的雷数量 for i, j in _get_around(x, y): if self._block[j][i].status == BlockStatus.flag: sumflag += 1 # 周边的雷已经全部被标记 result = True if sumflag == self._block[y][x].around_mine_count: for i, j in around: if self._block[j][i].status == BlockStatus.normal: if not self.open_mine(i, j): result = False else: for i, j in around: if self._block[j][i].status == BlockStatus.normal: self._block[j][i].status = BlockStatus.hint return result def double_mouse_button_up(self, x, y): self._block[y][x].status = BlockStatus.opened for i, j in _get_around(x, y): if self._block[j][i].status == BlockStatus.hint: self._block[j][i].status = BlockStatus.normal def _get_around(x, y): """返回(x, y)周围的点的坐标""" # 这里注意,range 末尾是开区间,所以要加 1 return [(i, j) for i in range(max(0, x - 1), min(BLOCK_WIDTH - 1, x + 1) + 1) for j in range(max(0, y - 1), min(BLOCK_HEIGHT - 1, y + 1) + 1) if i != x or j != y]
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