leetCode189.RotateArray数组
189. Rotate Array
站在用户的角度思考问题,与客户深入沟通,找到泰顺网站设计与泰顺网站推广的解决方案,凭借多年的经验,让设计与互联网技术结合,创造个性化、用户体验好的作品,建站类型包括:成都网站建设、网站设计、企业官网、英文网站、手机端网站、网站推广、域名注册、网页空间、企业邮箱。业务覆盖泰顺地区。
Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7]
is rotated to [5,6,7,1,2,3,4]
.
Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
题目大意:
将数组整体向右移动k位,多出来的移到数组前面。
思路:
用一个新数组来替换它即可。
代码如下:
class Solution { public: void rotate(vector& nums, int k) { if(k == 0 || nums.size() == 1 || nums.size() == 0) return; if(k > nums.size()) k = k % nums.size(); int i,count; count = 0; i = nums.size() - k; vector tmp; while(count != nums.size() ) { if(i >= nums.size() ) { i -= nums.size(); } tmp.push_back(nums[i]); i++; count++; } nums.swap(tmp); } };
2016-08-12 01:09:11
网站栏目:leetCode189.RotateArray数组
文章源于:http://scyanting.com/article/ghieij.html