spring命名出现Nopropertyuserfoundfortype怎么解决
这篇文章主要讲解了“spring命名出现No property user found for type怎么解决”，文中的讲解内容简单清晰，易于学习与理解，下面请大家跟着小编的思路慢慢深入，一起来研究和学习“spring命名出现No property user found for type怎么解决”吧！
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如果命名不正确会出现
Spring Data JPA: No property foo found for type Bar
No property user found for type
public interface UserRepository extends JpaRepository
User findByName(String userName);
}
可以看出实体类字段是userName,而repository却是findByName!改为findByUserName就好了
参考https://blog.csdn.net/j080624/article/details/82559318
https://www.cnblogs.com/oxygenG/p/10057525.html
| 关键字 | 方法命名 | sql where字句 |
| And | findByNameAndPwd | where name= ? and pwd =? |
| Or | findByNameOrSex | where name= ? or sex=? |
| Is,Equals | findById,findByIdEquals | where id= ? |
| Between | findByIdBetween | where id between ? and ? |
| LessThan | findByIdLessThan | where id < ? |
| LessThanEquals | findByIdLessThanEquals | where id <= ? |
| GreaterThan | findByIdGreaterThan | where id > ? |
| GreaterThanEquals | findByIdGreaterThanEquals | where id > = ? |
| After | findByIdAfter | where id > ? |
| Before | findByIdBefore | where id < ? |
| IsNull | findByNameIsNull | where name is null |
| isNotNull,NotNull | findByNameNotNull | where name is not null |
| Like | findByNameLike | where name like ? |
| NotLike | findByNameNotLike | where name not like ? |
| StartingWith | findByNameStartingWith | where name like '?%' |
| EndingWith | findByNameEndingWith | where name like '%?' |
| Containing | findByNameContaining | where name like '%?%' |
| OrderBy | findByIdOrderByXDesc | where id=? order by x desc |
| Not | findByNameNot | where name <> ? |
| In | findByIdIn(Collection c) | where id in (?) |
| NotIn | findByNameNot | where name <> ? |
| True | findByAaaTue | where aaa = true |
| False | findByAaaFalse | where aaa = false |
| IgnoreCase | findByNameIgnoreCase | where UPPER(name)=UPPER(?) |
| top | findTop100 | top 10/where ROWNUM <=10
|
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