vb.net编函数,编程语言 vb
使用vb.net编写一个函数,函数只有一个参数
首先在窗体上添加Button1,ListBox1,下面是完整代码
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Public Class Form1
Public Sub BubbleSort(ByVal arr() As Integer) '冒泡法排序
Dim temp As Double
Dim i, j As Integer
For i = 0 To arr.GetUpperBound(0) - 1
For j = i + 1 To arr.GetUpperBound(0) - 1
If arr(i) arr(j) Then
temp = arr(j)
arr(j) = arr(i)
arr(i) = temp
End If
Next
Next
End Sub
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click '调用
Dim arr() As Integer = {55, 22, 33, 11, 77, 88}
BubbleSort(arr) '调用排序过程
Me.ListBox1.Items.Clear()
For i = 0 To arr.GetUpperBound(0) - 1 '显示排序后结果
Me.ListBox1.Items.Add(arr(i).ToString)
Next
End Sub
End Class
VB.net 如何编写一个可以返回数组的函数(过程)?
public function createstringarr() as string()
return new string(){"d1","d2","d3","d4"}
end function
VB.NET自定义函数
很简单,在end select前再多加一种情况case else return "XXXx",因为你只提供了0-9这10种情况
Public Function Zuhe(ByVal qa As String) As String
Select Case qa
Case "0"
Return "1"
Case "1"
Return "3"
Case "2"
Return "4"
Case "3"
Return "6"
Case "4"
Return "2"
Case "5"
Return "8"
Case "6"
Return "9"
Case "7"
Return "7"
Case "8"
Return "5"
Case "9"
Return "0"
Case else
Return "XXXX"
End Select
End Function
vb.net 编写一个函数
注意:参数为动态数组;
Private Function MyF(ByRef d() As Integer)
ReDim d(4, 13) As Integer
Dim i As Integer
Dim j As Integer
Dim n As Integer
Dim MyNum(4) As Integer
For i = 1 To 4
MyNum(i) = 0
Next i
Randomize
For i = 1 To 4
For j = 1 To 13
n = Int(Rnd * 4 + 1)
Do While MyNum(n) = 13
n = Int(Rnd * 4 + 1)
Loop
d(i, j) = n
MyNum(n) = MyNum(n) + 1
Next j
Next i
End Function
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